(4x-8)(8x+12=

Solution for (4x-8)(8x+12= equation:

(4x-8)(8x+12=

We move all terms to the left:

(4x-8)(8x+12-()=0


We calculate terms in parentheses: +(4x-8)(8x+12-(), so:

4x-8)(8x+12-(

We add all the numbers together, and all the variables

4x-8)(8x

Back to the equation:

+(4x-8)(8x)


We multiply parentheses

32x^2-64x=0

a = 32; b = -64; c = 0;
Δ = b2-4ac
Δ = -642-4·32·0
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-64}{2*32}=\frac{0}{64}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+64}{2*32}=\frac{128}{64}
=2
$