4z-6=6(z+2)+84z-6=6(z+2)+8

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Solution for 4z-6=6(z+2)+84z-6=6(z+2)+8 equation: 



4z-6=6(z+2)+84z-6=6(z+2)+8

We move all terms to the left:

4z-6-(6(z+2)+84z-6)=0



We calculate terms in parentheses: -(6(z+2)+84z-6), so:

6(z+2)+84z-6

We add all the numbers together, and all the variables

84z+6(z+2)-6

We multiply parentheses

84z+6z+12-6

We add all the numbers together, and all the variables

90z+6

Back to the equation:

-(90z+6)



We get rid of parentheses

4z-90z-6-6=0

We add all the numbers together, and all the variables

-86z-12=0

We move all terms containing z to the left, all other terms to the right

-86z=12

z=12/-86

z=-6/43

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