2(3b+1)=2b+26

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Solution for 2(3b+1)=2b+26 equation: 



2(3b+1)=2b+26

We move all terms to the left:

2(3b+1)-(2b+26)=0

We multiply parentheses

6b-(2b+26)+2=0

We get rid of parentheses

6b-2b-26+2=0

We add all the numbers together, and all the variables

4b-24=0

We move all terms containing b to the left, all other terms to the right

4b=24

b=24/4

b=6

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