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2(3/2)+5d=2
We move all terms to the left:
2(3/2)+5d-(2)=0
determiningTheFunctionDomain 5d-2+2(3/2)=0
We add all the numbers together, and all the variables
5d-2+2(+3/2)=0
We add all the numbers together, and all the variables
5d-1=0
We move all terms containing d to the left, all other terms to the right
5d=1
d=1/5
d=1/5
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