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4(2y+3)=2(y-6)
We move all terms to the left:
4(2y+3)-(2(y-6))=0
We multiply parentheses
8y-(2(y-6))+12=0
We calculate terms in parentheses: -(2(y-6)), so:We get rid of parentheses
2(y-6)
We multiply parentheses
2y-12
Back to the equation:
-(2y-12)
8y-2y+12+12=0
We add all the numbers together, and all the variables
6y+24=0
We move all terms containing y to the left, all other terms to the right
6y=-24
y=-24/6
y=-4
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