2(3-4z)+7z=12z-(z+4)

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Solution for 2(3-4z)+7z=12z-(z+4) equation: 



2(3-4z)+7z=12z-(z+4)

We move all terms to the left:

2(3-4z)+7z-(12z-(z+4))=0

We add all the numbers together, and all the variables

2(-4z+3)+7z-(12z-(z+4))=0

We add all the numbers together, and all the variables

7z+2(-4z+3)-(12z-(z+4))=0

We multiply parentheses

7z-8z-(12z-(z+4))+6=0



We calculate terms in parentheses: -(12z-(z+4)), so:

12z-(z+4)

We get rid of parentheses

12z-z-4

We add all the numbers together, and all the variables

11z-4

Back to the equation:

-(11z-4)



We add all the numbers together, and all the variables

-1z-(11z-4)+6=0

We get rid of parentheses

-1z-11z+4+6=0

We add all the numbers together, and all the variables

-12z+10=0

We move all terms containing z to the left, all other terms to the right

-12z=-10

z=-10/-12

z=5/6

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