1/3(a+2)=1/2(4-a)

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Solution for 1/3(a+2)=1/2(4-a) equation: 



1/3(a+2)=1/2(4-a)

We move all terms to the left:

1/3(a+2)-(1/2(4-a))=0



Domain of the equation: 3(a+2)!=0

a∈R





Domain of the equation: 2(4-a))!=0

a∈R



We add all the numbers together, and all the variables

1/3(a+2)-(1/2(-1a+4))=0

We calculate fractions


(2a(-)/(3(a+2)*2(-1a+4)))+(-3aa/(3(a+2)*2(-1a+4)))=0



We calculate terms in parentheses: +(2a(-)/(3(a+2)*2(-1a+4))), so:

2a(-)/(3(a+2)*2(-1a+4))

We add all the numbers together, and all the variables

2a0/(3(a+2)*2(-1a+4))

We multiply all the terms by the denominator


2a0

We add all the numbers together, and all the variables

2a

Back to the equation:

+(2a)





We calculate terms in parentheses: +(-3aa/(3(a+2)*2(-1a+4))), so:

-3aa/(3(a+2)*2(-1a+4))

We multiply all the terms by the denominator


-3aa

Back to the equation:

+(-3aa)



We get rid of parentheses

2a-3aa=0

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