2(3-2x)=3(4-x)

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Solution for 2(3-2x)=3(4-x) equation: 



2(3-2x)=3(4-x)

We move all terms to the left:

2(3-2x)-(3(4-x))=0

We add all the numbers together, and all the variables

2(-2x+3)-(3(-1x+4))=0

We multiply parentheses

-4x-(3(-1x+4))+6=0



We calculate terms in parentheses: -(3(-1x+4)), so:

3(-1x+4)

We multiply parentheses

-3x+12

Back to the equation:

-(-3x+12)



We get rid of parentheses

-4x+3x-12+6=0

We add all the numbers together, and all the variables

-1x-6=0

We move all terms containing x to the left, all other terms to the right

-x=6

x=6/-1

x=-6

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