(2x+19)=(3x+35)

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Solution for (2x+19)=(3x+35) equation: 



(2x+19)=(3x+35)

We move all terms to the left:

(2x+19)-((3x+35))=0

We get rid of parentheses

2x-((3x+35))+19=0



We calculate terms in parentheses: -((3x+35)), so:

(3x+35)

We get rid of parentheses

3x+35

Back to the equation:

-(3x+35)



We get rid of parentheses

2x-3x-35+19=0

We add all the numbers together, and all the variables

-1x-16=0

We move all terms containing x to the left, all other terms to the right

-x=16

x=16/-1

x=-16

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