-7(t-3)+4t=3(6+t)

Solution for -7(t-3)+4t=3(6+t) equation:

-7(t-3)+4t=3(6+t)

We move all terms to the left:

-7(t-3)+4t-(3(6+t))=0

We add all the numbers together, and all the variables

-7(t-3)+4t-(3(t+6))=0

We add all the numbers together, and all the variables

4t-7(t-3)-(3(t+6))=0

We multiply parentheses

4t-7t-(3(t+6))+21=0


We calculate terms in parentheses: -(3(t+6)), so:

3(t+6)

We multiply parentheses

3t+18

Back to the equation:

-(3t+18)


We add all the numbers together, and all the variables

-3t-(3t+18)+21=0

We get rid of parentheses

-3t-3t-18+21=0

We add all the numbers together, and all the variables

-6t+3=0

We move all terms containing t to the left, all other terms to the right

-6t=-3

t=-3/-6

t=1/2