2(3-2f)=2(6-f)

Solution for 2(3-2f)=2(6-f) equation:

2(3-2f)=2(6-f)

We move all terms to the left:

2(3-2f)-(2(6-f))=0

We add all the numbers together, and all the variables

2(-2f+3)-(2(-1f+6))=0

We multiply parentheses

-4f-(2(-1f+6))+6=0


We calculate terms in parentheses: -(2(-1f+6)), so:

2(-1f+6)

We multiply parentheses

-2f+12

Back to the equation:

-(-2f+12)


We get rid of parentheses

-4f+2f-12+6=0

We add all the numbers together, and all the variables

-2f-6=0

We move all terms containing f to the left, all other terms to the right

-2f=6

f=6/-2

f=-3