2(3+x)=6x+18

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Solution for 2(3+x)=6x+18 equation: 



2(3+x)=6x+18

We move all terms to the left:

2(3+x)-(6x+18)=0

We add all the numbers together, and all the variables

2(x+3)-(6x+18)=0

We multiply parentheses

2x-(6x+18)+6=0

We get rid of parentheses

2x-6x-18+6=0

We add all the numbers together, and all the variables

-4x-12=0

We move all terms containing x to the left, all other terms to the right

-4x=12

x=12/-4

x=-3

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