8(y+4)+y=4(y+5)+4

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Solution for 8(y+4)+y=4(y+5)+4 equation: 



8(y+4)+y=4(y+5)+4

We move all terms to the left:

8(y+4)+y-(4(y+5)+4)=0

We add all the numbers together, and all the variables

y+8(y+4)-(4(y+5)+4)=0

We multiply parentheses

y+8y-(4(y+5)+4)+32=0



We calculate terms in parentheses: -(4(y+5)+4), so:

4(y+5)+4

We multiply parentheses

4y+20+4

We add all the numbers together, and all the variables

4y+24

Back to the equation:

-(4y+24)



We add all the numbers together, and all the variables

9y-(4y+24)+32=0

We get rid of parentheses

9y-4y-24+32=0

We add all the numbers together, and all the variables

5y+8=0

We move all terms containing y to the left, all other terms to the right

5y=-8

y=-8/5

y=-1+3/5

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