2(3+5x)=3(7x-4)-4

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Solution for 2(3+5x)=3(7x-4)-4 equation: 



2(3+5x)=3(7x-4)-4

We move all terms to the left:

2(3+5x)-(3(7x-4)-4)=0

We add all the numbers together, and all the variables

2(5x+3)-(3(7x-4)-4)=0

We multiply parentheses

10x-(3(7x-4)-4)+6=0



We calculate terms in parentheses: -(3(7x-4)-4), so:

3(7x-4)-4

We multiply parentheses

21x-12-4

We add all the numbers together, and all the variables

21x-16

Back to the equation:

-(21x-16)



We get rid of parentheses

10x-21x+16+6=0

We add all the numbers together, and all the variables

-11x+22=0

We move all terms containing x to the left, all other terms to the right

-11x=-22

x=-22/-11

x=+2

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