2(3+4x)+3(4-2x)=4(2-3x)

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Solution for 2(3+4x)+3(4-2x)=4(2-3x) equation: 



2(3+4x)+3(4-2x)=4(2-3x)

We move all terms to the left:

2(3+4x)+3(4-2x)-(4(2-3x))=0

We add all the numbers together, and all the variables

2(4x+3)+3(-2x+4)-(4(-3x+2))=0

We multiply parentheses

8x-6x-(4(-3x+2))+6+12=0



We calculate terms in parentheses: -(4(-3x+2)), so:

4(-3x+2)

We multiply parentheses

-12x+8

Back to the equation:

-(-12x+8)



We add all the numbers together, and all the variables

2x-(-12x+8)+18=0

We get rid of parentheses

2x+12x-8+18=0

We add all the numbers together, and all the variables

14x+10=0

We move all terms containing x to the left, all other terms to the right

14x=-10

x=-10/14

x=-5/7

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