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2(3+3x)=9(2)
We move all terms to the left:
2(3+3x)-(9(2))=0
determiningTheFunctionDomain 2(3+3x)-92=0
We add all the numbers together, and all the variables
2(3x+3)-92=0
We multiply parentheses
6x+6-92=0
We add all the numbers together, and all the variables
6x-86=0
We move all terms containing x to the left, all other terms to the right
6x=86
x=86/6
x=14+1/3
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