2(3+2x)=3(x-2)

Solution for 2(3+2x)=3(x-2) equation:

2(3+2x)=3(x-2)

We move all terms to the left:

2(3+2x)-(3(x-2))=0

We add all the numbers together, and all the variables

2(2x+3)-(3(x-2))=0

We multiply parentheses

4x-(3(x-2))+6=0


We calculate terms in parentheses: -(3(x-2)), so:

3(x-2)

We multiply parentheses

3x-6

Back to the equation:

-(3x-6)


We get rid of parentheses

4x-3x+6+6=0

We add all the numbers together, and all the variables

x+12=0

We move all terms containing x to the left, all other terms to the right

x=-12