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3(3x-2)=1/2(4+8x)
We move all terms to the left:
3(3x-2)-(1/2(4+8x))=0
Domain of the equation: 2(4+8x))!=0We add all the numbers together, and all the variables
x∈R
3(3x-2)-(1/2(8x+4))=0
We multiply parentheses
9x-(1/2(8x+4))-6=0
We multiply all the terms by the denominator
9x*2(8x+4))-(1-6*2(8x+4))=0
Wy multiply elements
18x^2(8-12x(8=0
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