2(2z-3)=3(z+2)+z

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Solution for 2(2z-3)=3(z+2)+z equation: 



2(2z-3)=3(z+2)+z

We move all terms to the left:

2(2z-3)-(3(z+2)+z)=0

We multiply parentheses

4z-(3(z+2)+z)-6=0



We calculate terms in parentheses: -(3(z+2)+z), so:

3(z+2)+z

We add all the numbers together, and all the variables

z+3(z+2)

We multiply parentheses

z+3z+6

We add all the numbers together, and all the variables

4z+6

Back to the equation:

-(4z+6)



We get rid of parentheses

4z-4z-6-6=0

We add all the numbers together, and all the variables

-12!=0

There is no solution for this equation

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