1/3(2x+4)+x=1/2(x+12)

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Solution for 1/3(2x+4)+x=1/2(x+12) equation: 



1/3(2x+4)+x=1/2(x+12)

We move all terms to the left:

1/3(2x+4)+x-(1/2(x+12))=0



Domain of the equation: 3(2x+4)!=0

x∈R





Domain of the equation: 2(x+12))!=0

x∈R



We add all the numbers together, and all the variables

x+1/3(2x+4)-(1/2(x+12))=0

We calculate fractions


x+(2xx/(3(2x+4)*2(x+12)))+(-3x2/(3(2x+4)*2(x+12)))=0



We calculate terms in parentheses: +(2xx/(3(2x+4)*2(x+12))), so:

2xx/(3(2x+4)*2(x+12))

We multiply all the terms by the denominator


2xx

Back to the equation:

+(2xx)





We calculate terms in parentheses: +(-3x2/(3(2x+4)*2(x+12))), so:

-3x2/(3(2x+4)*2(x+12))

We multiply all the terms by the denominator


-3x2

We add all the numbers together, and all the variables

-3x^2

Back to the equation:

+(-3x^2)



We get rid of parentheses

-3x^2+x+2xx=0

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