7y-2(y-6)=11y-(7y+13)

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Solution for 7y-2(y-6)=11y-(7y+13) equation: 



7y-2(y-6)=11y-(7y+13)

We move all terms to the left:

7y-2(y-6)-(11y-(7y+13))=0

We multiply parentheses

7y-2y-(11y-(7y+13))+12=0



We calculate terms in parentheses: -(11y-(7y+13)), so:

11y-(7y+13)

We get rid of parentheses

11y-7y-13

We add all the numbers together, and all the variables

4y-13

Back to the equation:

-(4y-13)



We add all the numbers together, and all the variables

5y-(4y-13)+12=0

We get rid of parentheses

5y-4y+13+12=0

We add all the numbers together, and all the variables

y+25=0

We move all terms containing y to the left, all other terms to the right

y=-25

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