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2(2z+5)=2(2z+5)=50
We move all terms to the left:
2(2z+5)-(2(2z+5))=0
We multiply parentheses
4z-(2(2z+5))+10=0
We calculate terms in parentheses: -(2(2z+5)), so:We get rid of parentheses
2(2z+5)
We multiply parentheses
4z+10
Back to the equation:
-(4z+10)
4z-4z-10+10=0
We add all the numbers together, and all the variables
=0
z=0/1
z=0
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