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2/3(3x-6)+2x=4-2(3x+1)
We move all terms to the left:
2/3(3x-6)+2x-(4-2(3x+1))=0
Domain of the equation: 3(3x-6)!=0We add all the numbers together, and all the variables
x∈R
2x+2/3(3x-6)-(4-2(3x+1))=0
We multiply all the terms by the denominator
2x*3(3x-6)-((4-2(3x+1)))*3(3x-6)+2=0
We calculate terms in parentheses: -((4-2(3x+1)))*3(3x-6), so:Wy multiply elements
(4-2(3x+1)))*3(3x-6
6x^2(3-((4-2(3x+1)))*3(3x-6)+2=0
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