2(2z+4)=6(5z+2)

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Solution for 2(2z+4)=6(5z+2) equation: 



2(2z+4)=6(5z+2)

We move all terms to the left:

2(2z+4)-(6(5z+2))=0

We multiply parentheses

4z-(6(5z+2))+8=0



We calculate terms in parentheses: -(6(5z+2)), so:

6(5z+2)

We multiply parentheses

30z+12

Back to the equation:

-(30z+12)



We get rid of parentheses

4z-30z-12+8=0

We add all the numbers together, and all the variables

-26z-4=0

We move all terms containing z to the left, all other terms to the right

-26z=4

z=4/-26

z=-2/13

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