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4*4x=x*5x+x*3
We move all terms to the left:
4*4x-(x*5x+x*3)=0
We add all the numbers together, and all the variables
4*4x-(+x*5x+x*3)=0
Wy multiply elements
16x-(+x*5x+x*3)=0
We get rid of parentheses
16x-x*5x-x*3=0
Wy multiply elements
-5x^2+16x-3x=0
We add all the numbers together, and all the variables
-5x^2+13x=0
a = -5; b = 13; c = 0;
Δ = b2-4ac
Δ = 132-4·(-5)·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-13}{2*-5}=\frac{-26}{-10} =2+3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+13}{2*-5}=\frac{0}{-10} =0 $
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