2(2y-2)+3(y+3)=19

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Solution for 2(2y-2)+3(y+3)=19 equation: 



2(2y-2)+3(y+3)=19

We move all terms to the left:

2(2y-2)+3(y+3)-(19)=0

We multiply parentheses

4y+3y-4+9-19=0

We add all the numbers together, and all the variables

7y-14=0

We move all terms containing y to the left, all other terms to the right

7y=14

y=14/7

y=2

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