4(4+2)=7(x-4)

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Solution for 4(4+2)=7(x-4) equation: 



4(4+2)=7(x-4)

We move all terms to the left:

4(4+2)-(7(x-4))=0

We add all the numbers together, and all the variables

-(7(x-4))+46=0



We calculate terms in parentheses: -(7(x-4)), so:

7(x-4)

We multiply parentheses

7x-28

Back to the equation:

-(7x-28)



We get rid of parentheses

-7x+28+46=0

We add all the numbers together, and all the variables

-7x+74=0

We move all terms containing x to the left, all other terms to the right

-7x=-74

x=-74/-7

x=10+4/7

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