2(2y+3)-3(y+1)=10y+5

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Solution for 2(2y+3)-3(y+1)=10y+5 equation: 



2(2y+3)-3(y+1)=10y+5

We move all terms to the left:

2(2y+3)-3(y+1)-(10y+5)=0

We multiply parentheses

4y-3y-(10y+5)+6-3=0

We get rid of parentheses

4y-3y-10y-5+6-3=0

We add all the numbers together, and all the variables

-9y-2=0

We move all terms containing y to the left, all other terms to the right

-9y=2

y=2/-9

y=-2/9

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