7n+3(n-2)=6(1+n)

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Solution for 7n+3(n-2)=6(1+n) equation: 



7n+3(n-2)=6(1+n)

We move all terms to the left:

7n+3(n-2)-(6(1+n))=0

We add all the numbers together, and all the variables

7n+3(n-2)-(6(n+1))=0

We multiply parentheses

7n+3n-(6(n+1))-6=0



We calculate terms in parentheses: -(6(n+1)), so:

6(n+1)

We multiply parentheses

6n+6

Back to the equation:

-(6n+6)



We add all the numbers together, and all the variables

10n-(6n+6)-6=0

We get rid of parentheses

10n-6n-6-6=0

We add all the numbers together, and all the variables

4n-12=0

We move all terms containing n to the left, all other terms to the right

4n=12

n=12/4

n=3

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