2(2y+2)+2(3y+3)=60

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Solution for 2(2y+2)+2(3y+3)=60 equation: 



2(2y+2)+2(3y+3)=60

We move all terms to the left:

2(2y+2)+2(3y+3)-(60)=0

We multiply parentheses

4y+6y+4+6-60=0

We add all the numbers together, and all the variables

10y-50=0

We move all terms containing y to the left, all other terms to the right

10y=50

y=50/10

y=5

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