2(2x-4)+(6-3x)=27

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Solution for 2(2x-4)+(6-3x)=27 equation: 



2(2x-4)+(6-3x)=27

We move all terms to the left:

2(2x-4)+(6-3x)-(27)=0

We add all the numbers together, and all the variables

2(2x-4)+(-3x+6)-27=0

We multiply parentheses

4x+(-3x+6)-8-27=0

We get rid of parentheses

4x-3x+6-8-27=0

We add all the numbers together, and all the variables

x-29=0

We move all terms containing x to the left, all other terms to the right

x=29

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