2(2x-1)+2(3x+4)=5(x-2)

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Solution for 2(2x-1)+2(3x+4)=5(x-2) equation: 



2(2x-1)+2(3x+4)=5(x-2)

We move all terms to the left:

2(2x-1)+2(3x+4)-(5(x-2))=0

We multiply parentheses

4x+6x-(5(x-2))-2+8=0



We calculate terms in parentheses: -(5(x-2)), so:

5(x-2)

We multiply parentheses

5x-10

Back to the equation:

-(5x-10)



We add all the numbers together, and all the variables

10x-(5x-10)+6=0

We get rid of parentheses

10x-5x+10+6=0

We add all the numbers together, and all the variables

5x+16=0

We move all terms containing x to the left, all other terms to the right

5x=-16

x=-16/5

x=-3+1/5

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