1/2(-10x+4)=-4(2x-3)+8

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Solution for 1/2(-10x+4)=-4(2x-3)+8 equation:



1/2(-10x+4)=-4(2x-3)+8
We move all terms to the left:
1/2(-10x+4)-(-4(2x-3)+8)=0
Domain of the equation: 2(-10x+4)!=0
x∈R
We multiply all the terms by the denominator
-((-4(2x-3)+8))*2(-10x+4)+1=0
We calculate terms in parentheses: -((-4(2x-3)+8))*2(-10x+4), so:
(-4(2x-3)+8))*2(-10x+4
We add all the numbers together, and all the variables
-10x+(-4(2x-3)+8))*2(+4
Back to the equation:
-(-10x+(-4(2x-3)+8))*2(+4)
We add all the numbers together, and all the variables
-(-10x+(-4(2x-3)+8))*24+1=0
We move all terms containing x to the left, all other terms to the right
-(-10x+(-4(2x-3)+8))*24=-1

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