2(2x+9)=4x+3-5(6-x)=

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Solution for 2(2x+9)=4x+3-5(6-x)= equation:



2(2x+9)=4x+3-5(6-x)=
We move all terms to the left:
2(2x+9)-(4x+3-5(6-x))=0
We add all the numbers together, and all the variables
2(2x+9)-(4x+3-5(-1x+6))=0
We multiply parentheses
4x-(4x+3-5(-1x+6))+18=0
We calculate terms in parentheses: -(4x+3-5(-1x+6)), so:
4x+3-5(-1x+6)
determiningTheFunctionDomain 4x-5(-1x+6)+3
We multiply parentheses
4x+5x-30+3
We add all the numbers together, and all the variables
9x-27
Back to the equation:
-(9x-27)
We get rid of parentheses
4x-9x+27+18=0
We add all the numbers together, and all the variables
-5x+45=0
We move all terms containing x to the left, all other terms to the right
-5x=-45
x=-45/-5
x=+9

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