3/7(x-2)=3/14(7+x)

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Solution for 3/7(x-2)=3/14(7+x) equation: 



3/7(x-2)=3/14(7+x)

We move all terms to the left:

3/7(x-2)-(3/14(7+x))=0



Domain of the equation: 7(x-2)!=0

x∈R





Domain of the equation: 14(7+x))!=0

x∈R



We add all the numbers together, and all the variables

3/7(x-2)-(3/14(x+7))=0

We calculate fractions


(42xx/(7(x-2)*14(x+7)))+(-21xx/(7(x-2)*14(x+7)))=0



We calculate terms in parentheses: +(42xx/(7(x-2)*14(x+7))), so:

42xx/(7(x-2)*14(x+7))

We multiply all the terms by the denominator


42xx

Back to the equation:

+(42xx)





We calculate terms in parentheses: +(-21xx/(7(x-2)*14(x+7))), so:

-21xx/(7(x-2)*14(x+7))

We multiply all the terms by the denominator


-21xx

Back to the equation:

+(-21xx)



We get rid of parentheses

42xx-21xx=0

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