2(2x+8)+2(3x+12)=320

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Solution for 2(2x+8)+2(3x+12)=320 equation: 



2(2x+8)+2(3x+12)=320

We move all terms to the left:

2(2x+8)+2(3x+12)-(320)=0

We multiply parentheses

4x+6x+16+24-320=0

We add all the numbers together, and all the variables

10x-280=0

We move all terms containing x to the left, all other terms to the right

10x=280

x=280/10

x=28

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