1-2(2x-3)=3-(3x+2)

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Solution for 1-2(2x-3)=3-(3x+2) equation: 



1-2(2x-3)=3-(3x+2)

We move all terms to the left:

1-2(2x-3)-(3-(3x+2))=0

We multiply parentheses

-4x-(3-(3x+2))+6+1=0



We calculate terms in parentheses: -(3-(3x+2)), so:

3-(3x+2)

determiningTheFunctionDomain
-(3x+2)+3

We get rid of parentheses

-3x-2+3

We add all the numbers together, and all the variables

-3x+1

Back to the equation:

-(-3x+1)



We add all the numbers together, and all the variables

-4x-(-3x+1)+7=0

We get rid of parentheses

-4x+3x-1+7=0

We add all the numbers together, and all the variables

-1x+6=0

We move all terms containing x to the left, all other terms to the right

-x=-6

x=-6/-1

x=+6

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