2(2x+3)=-6(x/9)

Solution for 2(2x+3)=-6(x/9) equation:

2(2x+3)=-6(x/9)

We move all terms to the left:

2(2x+3)-(-6(x/9))=0

We add all the numbers together, and all the variables

2(2x+3)-(-6(+x/9))=0

We multiply parentheses

4x-(-6(+x/9))+6=0

We multiply all the terms by the denominator


4x*9))-(-6(+x+6*9))=0

We add all the numbers together, and all the variables

4x*9))-(-6(x+54))=0

We add all the numbers together, and all the variables

4x*9))-(-6(x=0

Wy multiply elements

36x^2=0

a = 36; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·36·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{72}=0$