.3.14r2=314

Solution for .3.14r2=314 equation:

.3.14r^2=314

We move all terms to the left:

.3.14r^2-(314)=0

We add all the numbers together, and all the variables

0.042r^2-314=0

a = 0.042; b = 0; c = -314;
Δ = b2-4ac
Δ = 02-4·0.042·(-314)
Δ = 52.752
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{52.752}}{2*0.042}=\frac{0-\sqrt{52.752}}{0.084}
=-\frac{\sqrt{}}{0.084}
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{52.752}}{2*0.042}=\frac{0+\sqrt{52.752}}{0.084}
=\frac{\sqrt{}}{0.084}
$