2(2x)(x-8)=x+2

Solution for 2(2x)(x-8)=x+2 equation:

2(2x)(x-8)=x+2

We move all terms to the left:

2(2x)(x-8)-(x+2)=0

We multiply parentheses

22x^2-176x-(x+2)=0

We get rid of parentheses

22x^2-176x-x-2=0

We add all the numbers together, and all the variables

22x^2-177x-2=0

a = 22; b = -177; c = -2;
Δ = b2-4ac
Δ = -1772-4·22·(-2)
Δ = 31505
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-177)-\sqrt{31505}}{2*22}=\frac{177-\sqrt{31505}}{44}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-177)+\sqrt{31505}}{2*22}=\frac{177+\sqrt{31505}}{44}
$