2(2u-3)+5u=4(u-5)-2u

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Solution for 2(2u-3)+5u=4(u-5)-2u equation: 



2(2u-3)+5u=4(u-5)-2u

We move all terms to the left:

2(2u-3)+5u-(4(u-5)-2u)=0

We add all the numbers together, and all the variables

5u+2(2u-3)-(4(u-5)-2u)=0

We multiply parentheses

5u+4u-(4(u-5)-2u)-6=0



We calculate terms in parentheses: -(4(u-5)-2u), so:

4(u-5)-2u

We add all the numbers together, and all the variables

-2u+4(u-5)

We multiply parentheses

-2u+4u-20

We add all the numbers together, and all the variables

2u-20

Back to the equation:

-(2u-20)



We add all the numbers together, and all the variables

9u-(2u-20)-6=0

We get rid of parentheses

9u-2u+20-6=0

We add all the numbers together, and all the variables

7u+14=0

We move all terms containing u to the left, all other terms to the right

7u=-14

u=-14/7

u=-2

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