2(2u-3)+5u+5=4(u+5)+2u

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Solution for 2(2u-3)+5u+5=4(u+5)+2u equation: 



2(2u-3)+5u+5=4(u+5)+2u

We move all terms to the left:

2(2u-3)+5u+5-(4(u+5)+2u)=0

We add all the numbers together, and all the variables

5u+2(2u-3)-(4(u+5)+2u)+5=0

We multiply parentheses

5u+4u-(4(u+5)+2u)-6+5=0



We calculate terms in parentheses: -(4(u+5)+2u), so:

4(u+5)+2u

We add all the numbers together, and all the variables

2u+4(u+5)

We multiply parentheses

2u+4u+20

We add all the numbers together, and all the variables

6u+20

Back to the equation:

-(6u+20)



We add all the numbers together, and all the variables

9u-(6u+20)-1=0

We get rid of parentheses

9u-6u-20-1=0

We add all the numbers together, and all the variables

3u-21=0

We move all terms containing u to the left, all other terms to the right

3u=21

u=21/3

u=7

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