3(9t-3)=12+4-t+18

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Solution for 3(9t-3)=12+4-t+18 equation:



3(9t-3)=12+4-t+18
We move all terms to the left:
3(9t-3)-(12+4-t+18)=0
We add all the numbers together, and all the variables
3(9t-3)-(-1t+34)=0
We multiply parentheses
27t-(-1t+34)-9=0
We get rid of parentheses
27t+1t-34-9=0
We add all the numbers together, and all the variables
28t-43=0
We move all terms containing t to the left, all other terms to the right
28t=43
t=43/28
t=1+15/28

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