2(2t+4)=34(2/4-8t)

Solution for 2(2t+4)=34(2/4-8t) equation:

2(2t+4)=34(2/4-8t)

We move all terms to the left:

2(2t+4)-(34(2/4-8t))=0


Domain of the equation: 4-8t))!=0

We move all terms containing t to the left, all other terms to the right

-8t))!=-4

t!=-4/1

t!=-4

t∈R


We add all the numbers together, and all the variables

2(2t+4)-(34(-8t+2/4))=0

We multiply parentheses

4t-(34(-8t+2/4))+8=0

We multiply all the terms by the denominator


4t*4))-(34(-8t+2+8*4))=0

We add all the numbers together, and all the variables

4t*4))-(34(-8t+34))=0

We add all the numbers together, and all the variables

-8t+4t*4))-(34(=0

Wy multiply elements

16t^2-8t=0

a = 16; b = -8; c = 0;
Δ = b2-4ac
Δ = -82-4·16·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8}{2*16}=\frac{0}{32}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8}{2*16}=\frac{16}{32}
=1/2
$