2(2t+4)=3/4924-8t)

Solution for 2(2t+4)=3/4924-8t) equation:

2(2t+4)=3/4924-8t)

We move all terms to the left:

2(2t+4)-(3/4924-8t))=0


Domain of the equation: 4924-8t))!=0

We move all terms containing t to the left, all other terms to the right

-8t))!=-4924

t!=-4924/1

t!=-4924

t∈R


We add all the numbers together, and all the variables

2(2t+4)-(-8t+3/4924))=0

We multiply parentheses

4t-(-8t+3/4924))+8=0

We multiply all the terms by the denominator


4t*4924))+8-(-8t+3=0

Wy multiply elements

19696t^2=0

a = 19696; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·19696·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{0}{39392}=0$