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(25+2x)(21+4x)=714
We move all terms to the left:
(25+2x)(21+4x)-(714)=0
We add all the numbers together, and all the variables
(2x+25)(4x+21)-714=0
We multiply parentheses ..
(+8x^2+42x+100x+525)-714=0
We get rid of parentheses
8x^2+42x+100x+525-714=0
We add all the numbers together, and all the variables
8x^2+142x-189=0
a = 8; b = 142; c = -189;
Δ = b2-4ac
Δ = 1422-4·8·(-189)
Δ = 26212
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{26212}=\sqrt{4*6553}=\sqrt{4}*\sqrt{6553}=2\sqrt{6553}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(142)-2\sqrt{6553}}{2*8}=\frac{-142-2\sqrt{6553}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(142)+2\sqrt{6553}}{2*8}=\frac{-142+2\sqrt{6553}}{16} $
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