2(2t+4)=3/42(2t+4)=34(24-8t)(24-8t)

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Solution for 2(2t+4)=3/42(2t+4)=34(24-8t)(24-8t) equation: 



2(2t+4)=3/42(2t+4)=34(24-8t)(24-8t)

We move all terms to the left:

2(2t+4)-(3/42(2t+4))=0



Domain of the equation: 42(2t+4))!=0

t∈R



We multiply parentheses

4t-(3/42(2t+4))+8=0

We multiply all the terms by the denominator


4t*42(2t+4))-(3+8*42(2t+4))=0

Wy multiply elements

168t^2(2+336t(2=0

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