2(2t+4)=(72-24t)

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Solution for 2(2t+4)=(72-24t) equation:



2(2t+4)=(72-24t)
We move all terms to the left:
2(2t+4)-((72-24t))=0
We add all the numbers together, and all the variables
2(2t+4)-((-24t+72))=0
We multiply parentheses
4t-((-24t+72))+8=0
We calculate terms in parentheses: -((-24t+72)), so:
(-24t+72)
We get rid of parentheses
-24t+72
Back to the equation:
-(-24t+72)
We get rid of parentheses
4t+24t-72+8=0
We add all the numbers together, and all the variables
28t-64=0
We move all terms containing t to the left, all other terms to the right
28t=64
t=64/28
t=2+2/7

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