3(x2+5)=(x2-5)

Solution for 3(x2+5)=(x2-5) equation:

3(x2+5)=(x2-5)

We move all terms to the left:

3(x2+5)-((x2-5))=0

We add all the numbers together, and all the variables

3(+x^2+5)-((+x^2-5))=0

We multiply parentheses

3x^2-((+x^2-5))+15=0


We calculate terms in parentheses: -((+x^2-5)), so:

(+x^2-5)

We get rid of parentheses

x^2-5

Back to the equation:

-(x^2-5)


We get rid of parentheses

3x^2-x^2+5+15=0

We add all the numbers together, and all the variables

2x^2+20=0

a = 2; b = 0; c = +20;
Δ = b2-4ac
Δ = 02-4·2·20
Δ = -160
Delta is less than zero, so there is no solution for the equation