2(2t+4)=(18-6t)

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Solution for 2(2t+4)=(18-6t) equation: 



2(2t+4)=(18-6t)

We move all terms to the left:

2(2t+4)-((18-6t))=0

We add all the numbers together, and all the variables

2(2t+4)-((-6t+18))=0

We multiply parentheses

4t-((-6t+18))+8=0



We calculate terms in parentheses: -((-6t+18)), so:

(-6t+18)

We get rid of parentheses

-6t+18

Back to the equation:

-(-6t+18)



We get rid of parentheses

4t+6t-18+8=0

We add all the numbers together, and all the variables

10t-10=0

We move all terms containing t to the left, all other terms to the right

10t=10

t=10/10

t=1

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